Update CM20315_Training_II.ipynb
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@@ -114,7 +114,7 @@
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{
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{
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"cell_type": "code",
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"cell_type": "code",
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"source": [
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"source": [
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"# Initialize the parmaeters and draw the model\n",
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"# Initialize the parameters and draw the model\n",
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"phi = np.zeros((2,1))\n",
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"phi = np.zeros((2,1))\n",
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"phi[0] = 0.6 # Intercept\n",
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"phi[0] = 0.6 # Intercept\n",
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"phi[1] = -0.2 # Slope\n",
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"phi[1] = -0.2 # Slope\n",
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@@ -314,7 +314,7 @@
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" return compute_loss(data[0,:], data[1,:], model, phi_start+ gradient * dist_prop)\n",
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" return compute_loss(data[0,:], data[1,:], model, phi_start+ gradient * dist_prop)\n",
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"\n",
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"\n",
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"def line_search(data, model, phi, gradient, thresh=.00001, max_dist = 0.1, max_iter = 15, verbose=False):\n",
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"def line_search(data, model, phi, gradient, thresh=.00001, max_dist = 0.1, max_iter = 15, verbose=False):\n",
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" # Initialize four points along the rnage we are going to search\n",
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" # Initialize four points along the range we are going to search\n",
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" a = 0\n",
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" a = 0\n",
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" b = 0.33 * max_dist\n",
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" b = 0.33 * max_dist\n",
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" c = 0.66 * max_dist\n",
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" c = 0.66 * max_dist\n",
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@@ -345,7 +345,7 @@
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" # Rule #2 If point b is less than point c then\n",
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" # Rule #2 If point b is less than point c then\n",
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" # then point d becomes point c, and\n",
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" # then point d becomes point c, and\n",
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" # point b becomes 1/3 between a and new d\n",
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" # point b becomes 1/3 between a and new d\n",
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" # point c beocome 2/3 between a and new d \n",
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" # point c becomes 2/3 between a and new d \n",
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" if lossb < lossc:\n",
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" if lossb < lossc:\n",
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" d = c\n",
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" d = c\n",
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" b = a+ (d-a)/3\n",
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" b = a+ (d-a)/3\n",
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@@ -355,7 +355,7 @@
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" # Rule #2 If point c is less than point b then\n",
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" # Rule #2 If point c is less than point b then\n",
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" # then point a becomes point b, and\n",
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" # then point a becomes point b, and\n",
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" # point b becomes 1/3 between new a and d\n",
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" # point b becomes 1/3 between new a and d\n",
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" # point c beocome 2/3 between new a and d \n",
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" # point c becomes 2/3 between new a and d \n",
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" a = b\n",
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" a = b\n",
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" b = a+ (d-a)/3\n",
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" b = a+ (d-a)/3\n",
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" c = a+ 2*(d-a)/3\n",
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" c = a+ 2*(d-a)/3\n",
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